C 语言实例 – 计算一个数的 n 次方

#include <stdio.h>
 
int main()
{
    int base, exponent;
 
    long long result = 1;
 
    printf("基数: ");
    scanf("%d", &base);
 
    printf("指数: ");
    scanf("%d", &exponent);
 
    while (exponent != 0)
    {
        result *= base;
        --exponent;
    }
    printf("结果：%lld", result);
 
    return 0;
}

#include <stdio.h>
#include <math.h>
 
int main()
{
    double base, exponent, result;
 
    printf("基数: ");
    scanf("%lf", &base);
 
    printf("指数: ");
    scanf("%lf", &exponent);
 
    // 计算结果
    result = pow(base, exponent);
 
    printf("%.1lf^%.1lf = %.2lf", base, exponent, result);
 
    return 0;
}

#include <stdio.h>
 
int power(int n1, int n2);
 
int main()
{
    int base, powerRaised, result;
 
    printf("基数: ");
    scanf("%d",&base);
 
    printf("指数(正整数): ");
    scanf("%d",&powerRaised);
 
    result = power(base, powerRaised);
 
    printf("%d^%d = %d", base, powerRaised, result);
    return 0;
}
 
int power(int base, int powerRaised)
{
    if (powerRaised != 0)
        return (base*power(base, powerRaised-1));
    else
        return 1;
}